Mr RBPS Exam

Number Series  Rules with solved Aptitude Notes Mr RBPS Exam, Dear Readers , Since many Banking exams are in the streak and Maths section is like to be out of depth for many Aspirants. Here we are sharing Rules pertained to Number Series which is prepared and provided by one of our Ardent Readers Stallon. Number series form which at least 4- 5 questions use to come in the Banking Exams. We anticipate these would be viable to all of you. Number Series  Rules with solved Problems : Series is an important chapter from banking examination point of view. Following are some of the important rules or order on which the number series can be made :- Pure Series Difference Series Ratio Series Mixed Series Geometric Series Two Tier Arithmetic Series Other Types 1. Pure Series In this type of number series, the number itself obeys certain order so that the character of the series can be found out. The number itself may be.   Perfect Square Example : 121, 144, 169, 225 ? Answer - 256 ...

Boats And Streams Aptitude Notes Mr RBPS Exam, Type I: Finding Speed Of Boat Using Direct Formula In this type, you will be finding speed of boat in still water (i.e., when water is not flowing/running). You have to remember a very simple formula as shown below. Speed of the boat in still water = ½ (Downstream speed + Upstream speed) Here, downstream speed denotes the speed of the boat in the direction of the stream, and, upstream speed denotes the speed of the boat against the direction of the stream. 2 more basic formulas that will help you are given below. Downstream speed = Speed of boat in still water + Speed of stream Upstream speed = Speed of boat in still water – Speed of stream Let us see an example to understand this type. Example Question 1: A boat travels at 9 km/h along the stream and 6 km/h against the stream. Find the speed of the boat in still water. Solution: From the question, you can write down the below values. Downstream speed of the boat = 9 km/h Upstream speed o...

Age Problems Aptitude Notes Type 1: Ratio Based Age Problems (Why These Are Very Easy? Read On…) In this type, you will be given ratios between ages in question. You then have to then find the present ages of the people. In some cases, you may also be asked to find past or future ages. This the easiest type of age problems. You will know why after reading the below example. Example Question1: Ratio between ages of Rahul and Ravi is 3/5. After 10 years, the ratio will become 2/3. Find the present ages of Rahul and Ravi. To solve this, let us assume Rahul’s age to be x and Ravi’s age to be y. You can then write, x/y = 3/5 Or, 5x=3y Or, x=3y/5 ….equation 1 In question, you can find that after 10 years the ratio becomes 2/3. (After 10 years, Rahul’s age will become x+10 and Ravi’s age will become y+10) Therefore You can write, (x+10)/(y+10)=2/3 Or 3x+30 = 2y+20 Or 2y-3x=10 … equation 2 But, you already know from equation 1 that x = 3y/5. If you substitute this equation 2, you will get 2y-3...

Profit and Loss Aptitude Notes Type I:  Direct Formula Based Profit And Loss Percentages (Why This Is Easy?) This type is very straightforward and is formula based. This is very easy because, you have to remember just 4 very simple formulas to solve this type. Let CP be cost price of an item and SP be its selling price. If SP is greater than CP, then there is profit in the transaction. Profit value and percentage can be calculated using below two formulas: Profit = SP – CP Profit Percentage = (Profit / CP) x 100% If SP is lesser than CP, then there will be loss in the transaction. Loss value and percentage can be calculated using the below formulas. Loss = CP – SP Loss Percentage = (Loss / CP) x 100% Now, let us see an example question based on type 1. Example Question 1: Ram buys a book for Rs.100 and sells it for Rs.150. Find his gain or loss percentage. Solution: You can write down the CP and SP values from the question as follows: Cost Price CP =Rs.100 and Selling Price SP = Rs...

Pipe and Cisterns Aptitude Notes Nature of Pipe :                                               Inlet: A pipe connected with a tank or reservoir for filling is called as inlet Outlet: A pipe connected with a tank and used for empties it is called outlet. Concept: If a pipe can  a tank in x hours, then the part filled in 1 hour = 1 / x If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours, then the net part filled in 1 hour, when both the pipes are opened:   (1/x-1/y) Time taken to fill the tank, when both the pipes are opened: (x×y / y-x)  If a pipe can fill a tank in x hours and another fill the same tank in y hours, then the net part filled in 1 hr, when both pipes are opened: (1/x+1/y) So time to fill the tank will be:  [x×y/(x+y)] If a pipe fills a tank in x hrs and another fills the same tank in y hrs, bu...

Partnership Aptitude Notes Introduction:- When more than one person agree to invest their money to run a business or firm then this kind of agreement is called partnership. The persons involved in the partnership are called partners. There are two types of partnership. 1. Simple Partnership:In simple partnership, capitals of partners are invested for the same period of time. 2. Compound Partnership:In compound partnership, capitals of partners are invested for the different period of time. Basic Formulas If two partners A and B are investing their money to run a business then (Simple Partnership) Capital of A : Capital of B = Profit of A : Profit of B If two partners A and B are investing their money for different period of time to run a business then (Compound Partnership) Capital of A × Time period of A : Capital of B × Time period of B = Profit of A : Profit of B If n partners are investing for different period of time then C1T1 : C2T2 : C3T3 : … : CnTn = P1 : P2 : P3 : … : Pn Where...

Permutation & Combination and Probability Aptitude Notes Permutation& Combination and Probability: Permutation and Combination are not that important for the purpose of exam Because Question are rarely asked from This Topic but We have to learn them anyway because Question of probability can't be solved without learning permutation and combination. So will give you all a little hint about what is permutation and what is combination and then we will move on to Probability. But Before That Just Look at A very Important Concept Without Which You can't solve a single Question of permutation/combination or probability. And that Factorial Notation. It's represented by (!) and it is read as Factorial. So if i write 5! it will be read as Five Factorial. And what it means ? It means to simply multiply all the numbers in decreasing order till 1. Like if i write 6! it means 6*5*4*3*2*1 = 720 Or 7! = 7*6*5*4*3*2*1 = 5040 For Fast Calculation You all must learn the value of fact...

Time, Speed & Distance III Aptitude Notes Introduction: The terms time and distance are related to the speed of a moving object. Speed: Speed is defined as the distance covered by an object in unit time. Some Important Facts Distance travelled is proportional to the speed of the object if the time is kept constant. Distance travelled is proportional to the time taken if speed of object is kept constant. Speed is inversely proportional to the time taken if the distance covered is kept constant. If the ratio of two speeds for same distance is a:b then the ratio of time taken to cover the distance is b:a Relative Speed If two objects are moving in same direction with speeds of x and y then their relative speed is (x - y) If two objects are moving is opposite direction with speeds of x and y then their relative speed is (x + y) Unit Conversion Some Important Shortcut Formulas Rule 1: If some distance is travelled at x km/hr and the same distance is travelled at y km/hr then the average...

Time & Work Aptitude Notes Time and Work is a very easy topic and at least 2 Questions are asked from this topic in Any Exam whether it's Clerk or PO or SSC.What actually the Time and Work Topic is all about? In simple words It's how much time a person will take to Complete a Given Work. Here we are providing some cases of time and work and efficient method to solve it. Hope this would be helpful to all aspirants. These Tricks are shared by one of the our ardent BA reader Insomniac.We wish you good luck for your future. Note -: In conventional Method work is always treated as 1 Example: So if I say that a person can complete a work in 15 days that means he will do 1/15 work in one day, It's simple maths. Now another person does the same work in 30  days. So he will do 1/30 work in 1 day. Now if i ask in how many days they will complete the work together. What we gonna do is Add their 1 day of work  like 1/15 + 1/30 = (2+1)/30 = 3/30 = 1/10 Now this 1/10 we got is actual...